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In a series rlc circuit at resonance the magnitude of the voltage developed across the capacitor can be greater than the input voltage however it is 900 out of phase with the input voltage. When you apply dc voltage to a capacitor or an inductor they will store energy by forming an electric field.
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At this point the energy stored in the coils magnetic field induces a voltage across the coil because inductors oppose changes in current.
Voltage across capacitor in resonance. When you take away the voltage the stored energy will be flowing back into the circuit. The reason for this phenomenon is called resonance in this case between the capacitor and the inductor. So you can see how high voltages can result with incoming voltage of just 100 v.
At resonance in series rlc circuit both inductive and capacitive reactance cancel each other and we know that in series circuit the current flowing through all the elements is same. Since the values of qx s is very high a small harmonic current ip can cause large voltage to drop across the capacitor. Voltage across capacitor during parallel resonant condition there is very high voltage on the capacitor given by.
Actual voltages will depend on values of l and c in the circuit and the resistance in series. First current is the same value and same phase angle everywhere in a series circuit. If inductance is 1 h as example voltage across it will be 20 314 1 6280 v.
But voltage across a capacitor lags current by 90 degrees capacitor current leads voltage. Next voltage across a pure inductance leads current by 90 degrees inductor current lags voltage. In series rlc circuit the total voltage is the phasor sum of voltage across resistor inductor and capacitor.
At that point all the energy originally in the inductor when the switch closed has been transferred to the capacitor. Voltage across capacitor will then also be 6280 v in opposite phase. The voltage across the capacitor falls to zero as the charge is used up by the current flow.
A series resonance network consisting of a resistor of 30w a capacitor of 2uf and an inductor of 20mh is connected across a sinusoidal supply voltage which has a constant output of 9 volts at all frequencies. Eventually the backwards voltage across the inductor causes the inductor current to go to zero. The voltage on the cap rises as the first quadrant of a sine with the original voltage added.
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